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Whats the four terms of the recursively defined sequence:
bk = bk-1 + 3×k, for all k ³ 2, b1 = 2.

2007-07-16 01:59:24 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

b1=2
b2=2+6=8
b3=8+9=17
b4=17+12=29
b5=29+15=44

2007-07-20 02:00:02 · answer #1 · answered by robert 6 · 0 0

b2=2+6=8
b3=8+9=17
b4=17+12=29
b5=29+15=44

2007-07-16 02:13:51 · answer #2 · answered by santmann2002 7 · 0 0

a2 = 2*a1 + 4 = 2*5 + 4 = 14 a3= 2*a2 + 4 = 2*14 + 4 = 32 a4 = 2*a3 + 4 = 2*32 + 4 = 68

2016-05-19 00:46:03 · answer #3 · answered by ? 3 · 0 0

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