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The formula

1/R=(1/r1) + (1/r2)

determines the combined resistance R when resistors r1 and r2 are connected in parallel. Use total differentiation to determine the effect of a decreasing r1 to the combined resistance R.(assume that r2 is fixed.)

2007-07-16 01:31:15 · 2 answers · asked by physics maniac 2 in Science & Mathematics Mathematics

2 answers

If r2 is fixed, you wouldn't use total differentiation; you would use partial differentiation. I don't have access to the proper symbol, so I will still use d/d(r1).

1/R = (1/r1) + (1/r2) = (r1 + r2) / (r1*r2) => R = (r1*r2) / (r1 + r2)
d(R)/d(r1) = d[(r1*r2) / (r1 + r2)]/d(r1) = [(r1 + r2)(r2) - (r1*r2)*1] / (r1 + r2)^2 = [r1*r2 + (r2)^2 - r1*r2] / (r1 + r2)^2 = (r2)^2 / (r1 + r2)^2, where r2 is constant. I used the quotient rule for differentiation.

2007-07-16 01:46:11 · answer #1 · answered by DavidK93 7 · 0 0

R = r1*r2/(r1+r2)
dR= 1/(r1+r2)^2 [(r1+r2)*r2-r1*r2)]dr1 = -r2^2/(r1+r2)^2 *dr1

2007-07-16 08:47:39 · answer #2 · answered by santmann2002 7 · 0 0

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