2007-07-15 21:59:24 · 15 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Guys!
I know we all want to help people but look at all the math questions (s)he asked!
They are asking us to do their work. Stop supporting this. They are CHEATING.
I'm gonna report you. Yahoo doesn't permit people asking questions for ILLEGAL purposes.
2007-07-16 10:45:11 · answer #1 · answered by Marijn 3 · 0⤊ 0⤋
2x + 3y = 700 ..... (1)
3x + 4y = 975 ..... (2)
From (1), x = 350 - (3y/2)
Put this value of x in (2)
3(350 - 3y/2) + 4y = 975
1050 - 9y/2 + 4y = 975
-y/2 = -75
y/2 = 75
y = 150
Put y = 150 in (2),
3x + 600 = 975
3x = 375
x = 125
x = 125, y = 150 is the solution
2007-07-15 22:59:07 · answer #2 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
First equation:
2x + 3y = 700
2x = 700 - 3y
x = (700 - 3y)/2
Second equation:
3x + 4y = 975
3[(700 - 3y)/2] + 4y = 975
1050 - 4.5y + 4y = 975
-0.5y = -75
y/2 = 75
y = 150
First equation:
x = (700 - 3y)/2
= [700 - 3(150)]/2
= 125
so x = 125 and y = 150
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OR
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First equation:
2x + 3y = 700
3(2x + 3y) = 3(700)
6x + 9y = 2100
Second equation:
3x + 4y = 975
2(3x + 4y) = 2(975)
6x + 8y = 1950
First equation - Second equation:
(6x + 9y) - (6x + 8y) = 2100 - 1950
6x + 9y - 6x - 8y = 150
y = 150
Second equation:
6x + 8y = 1950
6x + 8(150) = 1950
6x = 1950 - 1200
6x = 750
x = 125
so x = 125 and y = 150
2007-07-15 22:08:53 · answer #3 · answered by Crammels 2 · 0⤊ 2⤋
the answer is:
x=125; y=150
2x + 3y = 700
solving for x:
x=(700-3y) / 2
3x + 4y = 975
substitute in the above equation the value of x...
3 ((700-3y)/2) +4y =975
simplify the equation by multiplying bothe sides by 2
3 (700-3y) +8y = 1950
2100 -9 y +8y = 1950
2100-1950 = 9y-8y
150 = y ^_^
substitute this value of y to the first equation
2x +3(150) = 700
x = 125 ^_^
hope this helps...
2007-07-15 22:09:10 · answer #4 · answered by kim 2 · 0⤊ 2⤋
x= 125
y= 150
3(2x + 3y = 700) = 6x+9y = 2100
2(3x + 4y = 975) = 6x+8y = 1950
subtract and you get y = 150
then substitute for y and solve for x
2007-07-15 22:05:57 · answer #5 · answered by siiimonnn 2 · 1⤊ 2⤋
(1) 2x + 3y = 700
(2) 3x +4y=975
(3)9x+12y=2925
(4)8x + 12y=2800
x=125
3(125) + 4y= 975
375+4y=975
4y=975-375
4y=600
600/4
y=150 x=125
2007-07-15 22:12:01 · answer #6 · answered by Anonymous · 0⤊ 2⤋
(2x + 3y=700) * -3
(3x + 4y=975)* 2
-6x - 9y = -2100
6x + 8y = 1950
y=150
x=125
2007-07-15 22:07:11 · answer #7 · answered by Anonymous · 1⤊ 2⤋
3*(2x+3y=seven hundred) =>6x+9y=2100 2*(3x+4y=975) =>6x+8y=1950 subtract a million. from 2. then y=one hundred fifty placed y's cost in first equation 2x+3*one hundred fifty=seven hundred =>2x+450=seven hundred =>2x=seven hundred-450 =>x=250/2 x=one hundred twenty five
2016-11-09 10:48:46 · answer #8 · answered by oppie 4 · 0⤊ 0⤋
2x + 3y = 700 .....(1)
3x + 4y = 975.........(2)
from (1)
2x=700-3y
x=(700-3y)/2.....(3)
put this value of x in (2)
3(700-3y)/2 + 4y = 975
Multiply by 2
3(700-3y)+8y=1950
2100-9y+8y=1950
-y=1950-2100
-y=-150
y=150
Put this value in (3)
x=(700-3*150)/2
x=(700-450)/2
x=250/2
x=125
2007-07-15 22:10:53 · answer #9 · answered by Jain 4 · 0⤊ 2⤋
x = 125
y = 150
2007-07-15 22:25:31 · answer #10 · answered by Timmy 1 · 0⤊ 1⤋
Multiplying the first equation by 3 we get,
6x + 9y = 2100......................Equation (3), say.
Multiplying the second equation by 2 we get,
6x + 8y = 1950......................Equation (4).
Equation (3) minus Equation (4) gives, y = 150.
Substituting, y =150 in Equation 1, we get,
2x + 3 X 150 = 700
i.e, 2x = 700 - 450 = 250
or x = 125.
So we have the values of both x and y, as 125 and 150, respectively. (Answer)
2007-07-15 22:18:45 · answer #11 · answered by Sam 7 · 0⤊ 2⤋