x + 3y = 17 ..... (1)
5x - 4y = -10 ..... (2)
From (1), x = 17 - 3y
Put this value of x in (2),
5(17 - 3y) - 4y = -10
85 - 15y - 4y = -10
-19y = -95
y = 5
Put y = 5 in (1)
x + 15 = 17
x = 2
So, x = 2, y = 5 is the solution.
2007-07-16 13:54:43
·
answer #1
·
answered by Akilesh - Internet Undertaker 7
·
1⤊
0⤋
ok simultaneous equation to solve by substition easy heres how to do ti
first numbber the equations
1) x + 3y = 17
2) 5x- 4y = -10
rearrange equation 1) to just be x= 17- 3y
if x = 17 -3y then 5x = 85 -15y
so we known that equation 2) is really 85 -15y - 4y = -10
collect the terms so 85 - 19y = -10
[-85 from both sides of the = ]
to get -19y = -95
divide by 19 on both sides to get -y = -5
therefore y = 5
then substiturtte the fact that y = 5 back in to equation 1) to get x + (3x5) = 17
therefore x=2
2007-07-15 22:04:36
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
hi, x + 3y = 17 solves to x = 17 - 3y 5x - 4y = -10 5(17 - 3y) - 4y = -10 eighty 5 - 15y - 4y = -10 eighty 5 - 19y = -10 -19y = -ninety 5 y = 5 If y = 5 and x = 17 - 3y, then x = 17 - 3(5) = 2 (2,5) <==answer i desire that helps!! :-)
2016-11-09 10:48:24
·
answer #3
·
answered by oppie 4
·
0⤊
0⤋
X + 3y = 17 and 5x - 4y = -10
x=17-3y 5(17-3y)-4y=-10
85-15y-4y=-10
85-19y=-10
-19y=-95
-5=y
x+3(-5)=17
x-15=17
x=2
2007-07-15 22:06:34
·
answer #4
·
answered by ? 4
·
0⤊
0⤋
x+3y=17(*)
5x-4y=-10
<=>5x+15y=85(1)
5x -4y=-10 (2)
(1)-(2)<=> 19y=95 <=> y=5
(8)=> x=2
2007-07-15 22:24:11
·
answer #5
·
answered by master.seiryu 1
·
0⤊
0⤋
x = 17 - 3y
5 (17 - 3y) - 4y = - 10
85 - 15 y - 4y = - 10
- 19 y = - 95
y = 5
x = 17 - 15
x = 2
Answer is x = 2 , y = 5
2007-07-16 05:09:19
·
answer #6
·
answered by Como 7
·
0⤊
0⤋
x=17 - 3y
Substitution:
5(17-3y) - 4y = -10
85 - 15y - 4y = -10
-19y=-95
y=5
x=2
2007-07-15 22:02:21
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
x+3y= 17
x= 17-3y
5x-4y=-10
5( 17-3y)-4y=-10
85-15y-4y=-10
-19y=-95
y=5
x=2
2007-07-15 22:17:03
·
answer #8
·
answered by Clov 2
·
0⤊
0⤋
x=17-3y
5x=85-15y
85-15y-4y=-10
19y=95
y=5
2007-07-15 22:00:31
·
answer #9
·
answered by Anonymous
·
0⤊
0⤋