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graph using the intercept method: x + 3y=6

2007-07-15 19:23:01 · 3 answers · asked by jovanni k 1 in Science & Mathematics Mathematics

3 answers

Set in slope intercept form, y = mx + b.

So, altering your original, it becomes y = -(1/3)x + 2.

To graph, start at 2 up on the y-axis. To find another point, go down one and right 3.

Connect the coordinates (0, 2) and (3, 1).

Line is thus graphed.

2007-07-15 19:31:12 · answer #1 · answered by dwalon2 4 · 0 0

Move the x to the right side of the equation. Divide each side by 3 to get y= -1/3x + 2. To graph, start at 2 on the y-axis. From there, go up 1 and left 3 for the next point. Draw a line through these two points to get your graph

2007-07-15 19:29:27 · answer #2 · answered by yankeesrus07 2 · 0 0

The intercept method takes advantage of two points on the x and y axes. If you locate these, you can draw the line of the equation.
So when x=0 (the vertical axis), y=2
And when y=0 (the horizontal axis), x=6
So the two points are (0,2) and (6,0)

2007-07-15 19:33:18 · answer #3 · answered by cattbarf 7 · 1 0

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