Joules of heat energy?

Question

How many joules of heat energy are required to raise the temp of 10 grams of liquid water from 25 degree Celcius to 35 degree Celcius?

Answer 1

water needs 4.184 J of energy to raise the temp of 1 g of it through 1 degree celcius .
so ans is =4.184 X 10 X 10 =418.4J

Answer 2

Recall that 1 Joule is the amount of heat energy that raises 1 cubic centimeter of water by 1 degree Celsius.

You have 10 grams of water, which is 10 cubic centimeters. You want to raise the temperature by 10 degrees Celsius.

10 times the amount of water, and 10 times the temperature charge, means you'll need 100 times the energy. So, 100 Joules is your value.

Answer 3

for this question you must use the delta H formula. Delta H = mc(delta)H (change in temperature). Here's the work, hopefully you can understand it. (15g)(4.2J/g)(10C) 1. You can get 10C by subtracting the 40C-30C=10C. (63)(10C) 2. You get the 4.2 J/g from the reference table, Table B. 630 3. Multiply them all together The answer is 4. 630

Answer 4

The Specific heat of water = 4.184J/g/°C. (mass(g) not cc).
4.184J x 10g x 10°C = 418.4Joules.