If x ^(2) - 3x -2 = 0,
then what is the value of 2x^(2) - 6x - 11 ?
a) -9 b) -7 c) 0 d) 7 e) 9
If (4x + 3y) / (16x^2 - 9y^2) = 10, what is the value of 4x - 3y ?
a) 0.01 b) 0.1 c) 1 d) 7 e) 10
plz show work or explain
2007-07-15 12:25:37 · 3 answers · asked by ? 2 in Science & Mathematics ➔ Mathematics
x^2-3x-2 = 0
x^2-3x = 2 i.e, 2x^2-6x = 4
Hence 2x^2-6x-11 = 4-11 =-7 answer b) -7
16x^2 - 9y^2 = (4x+3y) * (4x-3y)
(4x + 3y)/ (16^2 - 9y^2) = 1/(4x-3y) = 10
4x-3y = 1/10 = 0.1 answer b) 0.1
2007-07-15 12:37:00 · answer #1 · answered by yogesh u 3 · 2⤊ 0⤋
the first problem cant be factored, and you cant do what yogesh u did because 2x^(2) - 6x - 11 isnt and equation. I tried to factor it and i tried the quadratic formula but it doesnt work.
2007-07-15 19:49:23 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x^2 - 3x - 2 = 0
cannot be factored
(4x+3y)/(4x+3y)(4x-3y) = 10
1/(4x-3y) = 10
10(4x-3y) = 1
4x-3y = 1/10
2007-07-15 19:31:13 · answer #3 · answered by gebobs 6 · 0⤊ 0⤋