simplify the following problems:?

Question

1/x-1 - 2/x^2-1


(x+1)/x^2+2x+1


x^2+3x/x^2+2x-3 divide x/x+1

Answer 1

1/x-1 - 2/x^2-1
= 1/x-1 - 2/(x-1)(x+1)
= [1(x+1)-2]/(x-1)(x+1)
= [ x-1]/(x-1)(x+1)
= 1/(x+1)

(x+1)/x^2+2x+1
=(x+1)/(x+1)(x+1)
= 1/(x+1)

x^2+3x/x^2+2x-3 divide x/x+1
=x^2+3x/x^2+2x-3 *x+1/x
=[x(x+3)*(x+1)]/[(x+3)(x-1)*x;
=(x+1)/(x-1)

Answer 2

1/x-1 - 2/x^2-1= 1/x+1

(x+1)/x^2+2x+1= 1/x+1

x^2+3x/x^2+2x-3= x/x-1

These are in simplest form.

Answer 3

1/(x-1) - 2/(x+1)(x-1)
(x+1)/(x+1)(x-1) - 2/(x+1)(x-1)
(x-1)/(x+1)(x-1)
1/(x+1)

(x+1)/x^2 + 2x(x^2)/x^2 + x^2/x^2
(x+1+2x^3+x^2)/x^2
(2x^3+x^2+x+1)/x^2

(x^2+3x)/(x^2+2x-3)/x/(x+1)
(x+3)(x+1)/(x+3)(x-1)
(x+1)/(x-1)

By the way, if you use parentheses, your problems would be less open to interpretation...or not at all preferably.

For example, Harry and I both have valid interpretations of the second equation and come up with completely different answers.

When you are asking for this much help, don't be lazy. Help us help you.

Answer 4

1/(x-1)-2/(x-1)(x+1)
Or {(x+1)-2}/(x-1)(x+1)
Or(x-1)/(x-1)(x+1)
or 1/(x+1) ans
TRY OTHERS ON THE SAME LINES

Answer 5

1)
1/x-1 - 2/x^2-1
=(x^2-1-2x+2)/(x^2-1)(x-1)
=(x^2-2x+1)/(x^2-1)(x-1)
=(x-1)^2/(x^2-1)(x-1)
=(x-1)/(x^2-1)

2)
(x+1)/x^2+2x+1
=(x+1)/(x+1)^2
=1/(x+1)

3)
x^2+3x/x^2+2x-3 divide x/x+1
=(x^2+3x)(x+1)/x(x^2+2x-3)
=(x^3+4x^2+3x)/x(x+3)(x-1)
=x(x^2+4x+3)/x(x+3)(x-1)
=x(x+1)(x+3)/x(x+3)(x-1)
=(x+1)/(x-1)

Answer 6

2? - ?/2 < x < 2? + ?/2 a million.5? < x < 2.5? (you have greater advantageous than or equivalent too indicators which i won't be able to get) Do you purely % this inequality or do you % integer values for x or what? Ahh then x = 5, 6 & 7

Answer 7

1. 1/x+1
I had assumed wrong previously