1. (4x^2/3y^2) (2y^3/x^2)
2. (x^4/4y^3)(2y/x^3)^3
3. (x^3y^-2/x^-3y^2)^-1
4. 6x^3/y^2 divide 3xy/2
2007-07-15 08:45:50 · 5 answers · asked by callmejeseca 1 in Science & Mathematics ➔ Mathematics
1. 8x^2y^3/3x^2y^2
...8y/3
2. 8x^4y^3/4y^3x^9
...8/x^5
3. pffft...you could interpret that one a hundred ways.
4. 6x^3/y^2/3xy/2
...12x^3/3xy^3
...4x^2/y^3
2007-07-15 08:55:17 · answer #1 · answered by gebobs 6 · 0⤊ 0⤋
1.
(4x^2/3y^2) (2y^3/x^2)
=(4x^2*2y^3)/(3y^2 x^2)
=8y/3
2.
(x^4/4y^3)(2y/x^3)^3
=(x^4*8y^3)/(4y^3 x^9)
=2/x^5
3.
(x^3y^-2/x^-3y^2)^-1
=(x^-3 y^2)/(x^3 y^-2)
=y^4/x^6
4.
6x^3/y^2 divide 3xy/2
=2(6x^3)/3xy(y^2)
=12x^3/3xy^3
=4x^2/y^3
2007-07-15 08:57:57 · answer #2 · answered by fofo m 3 · 0⤊ 0⤋
Jeseca, start wearing a thong, go to clubs showing a little cleavage, dance sexy with other girls while almost kissing them and make the boys go wild, then get laid good. You will have plenty of time later to ask meaningless mathematical questions that attract a future dork husband that has a well paying job and takes care of you.
2007-07-15 08:59:14 · answer #3 · answered by sunshine_sera 1 · 0⤊ 0⤋
1.(4x^2/3y^2)(2y^3/x^2)=(8y/3)
2.(x^4/4y^3)(2y/x^3)^3=(x^4/4y^3)(8y^3/x^9)
=(2/x^5)
3.(x^3y^-2/x^-3y^2)^-!=(x^6/y^4)-1
=(y^4/x^6)
4.(6x^3/y^2)/(3xy/2)=(6x^3/y^2)*(2/3xy)
=(4x^2/y^3)
2007-07-15 09:00:31 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Do your own homework!! jk jk
Um I havent learned any of that yet...sorry
2007-07-15 08:53:31 · answer #5 · answered by Emily 2 · 0⤊ 0⤋