2007-07-15 08:29:00 · 8 answers · asked by Bobby 1 in Science & Mathematics ➔ Mathematics
its actually
Solve: Log X^2 = 6
2007-07-15 08:29:46 · update #1
log(x^2) = 6
x^2 = 10^6
x = ±(10^6)^(1/2) = ±(10^3) = ±1000
Don't forget the plus/minus! There are technically two answers to this problem!
Hope this helps!
2007-07-15 08:33:26 · answer #1 · answered by Doorrat 3 · 0⤊ 0⤋
Let log mean log to base 10 in the following:-
log x² = 6
2 log x = 6
log x = 3
x = 10³
x = 1000
2007-07-15 23:18:29 · answer #2 · answered by Como 7 · 0⤊ 0⤋
LOGx^2=6
so 10^6=x^2
or x^2=10^6
or x=+-(10)^6/2=+-10^3=+-1000 ans
2007-07-15 08:52:13 · answer #3 · answered by MAHAANIM07 4 · 0⤊ 0⤋
log x^2 = 6
change to exponent form
10^6 = x^2
x^2 = 1,000,000
x = +/- 1000
but -1000 won't work, so +1000 is the answer
2007-07-15 08:35:36 · answer #4 · answered by 7 · 0⤊ 0⤋
log(base k)(x^2) = 6
x^2 = k^6
x = +/-k^3 where k is he base of the log.
2007-07-15 08:32:08 · answer #5 · answered by Anonymous · 0⤊ 0⤋
log(x^2)=6
2log x=6
log x=6/2=3
log x=3
log 10^3=3log10 here log10=1 so, x=10^3=1000
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.if x^2=6............x=2.45...
2007-07-15 08:38:44 · answer #6 · answered by Tuncay U 6 · 0⤊ 0⤋
x^2=6
x=sqrt(6).
x=2.45. ANS
2007-07-15 08:34:40 · answer #7 · answered by Anonymous · 0⤊ 0⤋
log(x^2)=6
x^2=10^6
x^2=1000000
x=1000
2007-07-15 08:32:43 · answer #8 · answered by Math Man 3 · 0⤊ 0⤋