8x^2 - 32x +24
2007-07-15 06:54:05 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
8(x² - 4x + 3)
Want: x² - 4x + 3 = (x-r)(x-s) for roots r and s.
That means x² - 4x + 3 = x² - (r+s)x + (rs).
r+s = 4
rs = 3
So the roots add to 4 and multiply to 3. Obvious that they are 1 and 3.
Final answer:
8(x - 3)(x - 1)
2007-07-15 06:57:00 · answer #1 · answered by сhееsеr1 7 · 0⤊ 1⤋
Hey there!
Here's the answer.
8x^2-32x+24 -->
8(x^2-4x+3) -->
8(x^2-3x-x+3) -->
8(x(x-3)-1(x-3)) -->
8(x-1)(x-3)
So the answer is 8(x-1)(x-3).
Hope it helps!
2007-07-15 13:59:03 · answer #2 · answered by ? 6 · 0⤊ 0⤋
8x² - 32x + 24 = 0
Common factor
8(x² - 4x + 3) = 0
8(x² - 1x - 3x + 3) = 0
8[x(x - 1) - 3(x - 1) = 0
8(x - 3)(x - 1) = 0
- - - - - - -s-
2007-07-15 14:14:31 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
8*(x-1)*(x-3)
2007-07-15 13:59:23 · answer #4 · answered by ? 5 · 0⤊ 0⤋