3x^2 +23x -36
2007-07-15 06:52:03 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3x² + 23x - 36 = 0
3x² + 27x - 4x - 36 = 0
3x(x + 9) - 4(x + 9) = 0
(3x - 4)(x + 9) = 0
- - - - - -s-
2007-07-15 07:22:06 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
3x^2 +23x -36
= (3x-4)(x+9)
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Ideas: Factor -36*3 = -108 into 27 and -4 such that 27+-4 = 23, the coefficient of the linear term 23x.
2007-07-15 13:56:20 · answer #2 · answered by sahsjing 7 · 1⤊ 0⤋
Hey there!
Here's the answer.
3x^2+23x-36 -->
3x^2+27x-4x-36 -->
3x(x+9)-4(x+9) -->
(3x-4)(x+9)
So the answer is (3x-4)(x+9).
Hope it helps!
2007-07-15 14:00:45 · answer #3 · answered by ? 6 · 0⤊ 0⤋
3X^2+23X-36
3X^2+27X-4X-36
3X(X+9)-4(X+9)
(3X-4)(X+9) ans
2007-07-15 14:33:20 · answer #4 · answered by MAHAANIM07 4 · 0⤊ 0⤋