thanks for any help given, i'm no good at math
2007-07-15 06:07:10 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
h(x) = (2-x) / (5x + 6)
Use quotient rule:
h'(x) = [(5x+6)(-1) - (2-x)(5)] / [(5x+6)^2]
= (-5x - 6 -10 + 5x) / (5x+6)^2
= (-16) / (5x+6)^2
Puggy's answer has a minor arithmetic error.
2007-07-15 06:32:01 · answer #1 · answered by whitesox09 7 · 0⤊ 0⤋
h(x) = (2 - x)/(5x + 6)
Use the quotient rule. "The derivative of the top times the bottom minus the derivative of the bottom times the top, over the bottom squared."
h'(x) = [ (-1)(5x + 6) - (2 - x)(5) ] / (5x + 6)^2
Simplify the numerator,
h'(x) = [ -5x - 6 - 5(2 - x) ] / (5x + 6)^2
h'(x) = [ -5x - 6 - 10 + 5x ] / (5x + 6)^2
h'(x) = (-4)/(5x + 6)^2
2007-07-15 06:15:39 · answer #2 · answered by Puggy 7 · 0⤊ 0⤋
factor the two the numerator and denominator. components could desire to have the capacity to cancel out. 5x^2 + x - 6 ----------------- 5x^2 - 9x - 18 = (x - a million)(5x + 6) -------------------- (x - 3)(5x + 6) (5x + 6) and (5x + 6) cancel out to a million, so we are left with... (x - a million) -------- (x - 3) =]
2016-11-09 09:32:00 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Use quotient rule:-
h (x) = u / v
h `(x) = [ v du/dx - u dv / dx ] / v²
u = 2 - x
du / dx = - 1
v = 5x + 6
dv / dx = 5
h `(x) = [(5x + 6) (-1) - (2 - x)(5)] / (5x + 6)²
h `(x) = [- 5x - 6 - 10 + 5x ] / (5x + 6)²
h `(x) = - 16 / (5x + 6)²
2007-07-16 10:51:56 · answer #4 · answered by Como 7 · 0⤊ 0⤋