maths question nid it now rite now?

Question

Adam has 3times as many stamps as Xinlong and an additional 6 stamps,Cindy has 1/6 of What adam has and additonal 2 stamps,Cindy has 4 stamps fewer than xin long.
A)how many stamps do they have altogether?
B)How many stamps must adam give xinlong so that they will have the same number of stamps?

Answer 1

Let, adam's count be y
xin-long's count be x

adam (y) = 3x + 6
y - 3x = 6............A

cindy - 1/6(y) + 2
cindy - x - 4
1/6(y) + 2 = x -4
y - 6x = - 36..............B

Now we've got 4 eqs. A and B,

y - 3x = 6
y - 6x = -36

subract the eqs.

-3x = - 42
x = 14

x = 14..........xin-long has 14 stamps
x - 4 = 10.........cindy has 10 stamps
3x + 6 = 48.........adam has 48 stamps

b.) Adam must give 17 stamps so that they both will have 31 stamps.

Answer 2

Adam = A
Xinlong = X
Cindy = C

A = 3X + 6 .............(1)
C = A/6 + 2 ............(2)
and also, C = X - 4 ................(3)

Substitute (1) in (2) TO GET (4)
we get, C = (3X + 6)/6 + 2
C = [(X + 2) + 4] / 2] ..................(4)

((X + 2) + 4) / 2 = X - 4
(X + 6)/2 = X - 4
X + 6 = 2X - 8
X = 14

Xin long has 14 stamps
Adam (A = 3X + 6) = 3(14) +6 = 48 stamps
Cindy(X - 4) = 14 - 4 = 10 stamps

A) total stamps they all have together = 14 + 48 + 10 = 72 stamps

b) (48 + 14) / 2 = 31
each one should have 31 stamps
48 - 31 = 17 stamps
adam should give xinlong 17 stamps so that they will have equal number of stamps...

hope this helps!! :-)

Answer 3

Let x = Xinlong's # of stamps
3x+6 = Adam's
x - 4 = 1/6(3x+6) +2 = Cindy's

1/6(3x+6) + 2 = x-4
1/2x+ 3= x-4
x=14

x=14 - Xinlong
3x+6=48 - Adam
x-4=10 - Cindy

Total of 72 stamps

B) 48+14 = 62
62/2 = 31
Adam must give 17 stamps to Xinlong in order for them to both have 31 stamps.

Answer 4

let x = adam stamps
y = for Xinlong
z = for Cindy

x = 3y + 6
y = z + 4
z = x/6 + 2

subtitute z in y:
y = z + 4
y = (x/6 + 2) + 4
y = x/6 + 6

substitute y in x:
x = 3y + 6
x = 3(x/6 +6) +6
x = x/2 + 18 + 6
x- x/2 = 24
x/2 = 24
x = 48 for Adam

substitute x in z:
z = x/6 + 2
z = 48/6 + 2
z = 8 + 2
z = 10 for Cindy

sbstitute z in y:
y = z + 4
y = 10 + 4
y = 14 for Xinlong

Total stamps = x + y + z
= 48 + 14 + 10
= 72 stamps

to get same number of stamps each for adam and xinlong

= (48 + 14) / 2
= 31 stamps
xinlong needs 17 stamps,
adam must give 17 stamps to xinlong to have the same number of stamps...

Answer 5

let x = stamps of Xinlong
3x + 6 = Stamps of Adam
1/6(3x + 6) + 2 = stamps of Cindy
x - 4 = also the stamps of Cindy
1/6(3x + 6) + 2 = x - 4
x/2 + 1 + 2 = x - 4
x/2 = 7
x = 14 . . . is the number of stamps of Xinlong
3x + 6 = 48 . . is the number of stamps of Adam
x - 4 = 10 . . is the number of stamps of Cindy

Answer 6

a=Adam's stamps
x=Xin Long's stamps
c=Cindy's stamps

a=3x+6
c=x-4
c=a/6+2 so
a=(c-2)6=6c-12

so substitute
6(x-4)-12=3x+6
6x-24-12=3x+6
6x-3x=6+24+12
3x=42
x=14

c=x-4=14-4=10
a=3x+6=3(14)+6=42+6=48

Adam has 48 stamps
Xin Long has 14 stamps
Cindy has 10 stamps

to get Adam and Xin Long even 48+14=62
62/2=31
so each need 31 stamps 48-31=17

so if Adam gives Xin Long 17 stamps they each have the same amount

Answer 7

Let Adam have x stamps
Xinlong has (x-6)/3
Cindy has x/6 +2
We know (x/6 +2) +4 = (x-6)/3
So, x/6 +6 = (x-6)/3
So, x +36 = 2x - 12
So, x = 48
Adam has 48, Xinlong has 14, Cindy has 10
Altogether they have 72

Xinlong + Adam = 62
Half of 62 =31
So Adam would have to give Xinlong 17 stamps.

Answer 8

A = 3X + 6
C = A/6 + 2
X = C + 4
A = 3(C + 4) + 6
A = 3(A/6 + 2) + 12 + 6
A = A/2 + 6 + 18
A = 48
C = 10
X = 14
A) A + X + C = 72
B) (48 - 14)/2 = 17

Answer 9

let no. stamps sin has be X,
then adam has 3X+6.
then cindy has 1/6(3X+6)+2=X/2+1+2=(x+6)/2
now frm the question we know that
(X+6)/2=X-4
solving we get
X=14.
a)72
b)17

Answer 10

try English as well