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10 answers

It's 3 out of 4. To see why, the possible outcomes are ee, eo, oe, and oo.

If the question asks what's the odds of getting a odd SUM, then it's 1 out of 2.

Addendum: As for the question of the odds of throwing an odd number after the die has been thrown N times, if it has turned up odds substantially higher than N/2 times, then the odds is probably higher than 1/2, because you could have a crooked die.

2007-07-13 18:52:41 · answer #1 · answered by Scythian1950 7 · 0 0

I'm assuming you mean getting an odd number either time. The probability is 3/4 or 75%. You have a 50% chance both rolls -- combining the probabilities gives you 75% chance for hitting one odd number in two rolls.

2007-07-13 18:53:57 · answer #2 · answered by Jonny Jo 3 · 0 0

The probability of getting an odd number at least once is one out of 75%.

The probability of getting an odd number both times is 25%.

The probability of the sum of the two rolls adding up to an odd number is 50%.

2007-07-13 18:53:29 · answer #3 · answered by G J 2 · 2 0

probability of getting one six = 1/6 probability of getting another six = 1/6 * the first probability = 1/6 * 1/6 = 1/36 probability of getting not a six on the second try = 5/6 * the first probability = 5/6 * 1/6 = 5/36 probability of getting a six on the second try but not the first = 1/6 * the probability of not getting a six the first time = 1/6 * 5/6 = 5/36

2016-05-17 08:34:43 · answer #4 · answered by ? 3 · 0 0

3 out of 6

2007-07-13 18:51:26 · answer #5 · answered by Anonymous · 1 0

probability of getting an odd number in first throw = 3/6
probability of getting an odd number in second throw = 3/6

chances of getting an odd number in both throws = (3/6)*(3/6) = 1/4 = 25%

similarly chances of getting an even number in both throws = 1/4
so, chances of getting an odd number in atleast one of two throws = 1 - 1/4 = 3/4 = 75%

2007-07-13 18:56:06 · answer #6 · answered by Vipin A 3 · 0 0

the probability is 3 out of 6 or 1/2

2007-07-13 18:55:46 · answer #7 · answered by Anonymous · 0 1

Can get odd number on 1st throw OR 2nd throw or 1st AND 2nd throw
P(odd number)
= (1/2) + (1/2) - (1/2) (1/2)
= 1 - 1/4
= 3/4

2007-07-14 21:48:37 · answer #8 · answered by Como 7 · 0 0

3/6 since 3 out of those 6 numbers are odd

2007-07-13 18:56:06 · answer #9 · answered by Anonymous · 0 1

It is three out of six, or 50%, regardless of how many times you roll the die. Each roll is independant of the other. For instance if you roll the die nine times, and it lands odd each time, then tenth time you roll the die, it does not know that it landed odd the previous nine times, hope that makes sense, but, that is the answer, refer to any stat. book for reference.

2007-07-13 19:10:05 · answer #10 · answered by grouch2111 6 · 0 0

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