how do you this exactly? ive forgotten how to do functions
2007-07-13 17:43:02 · 6 answers · asked by ? 2 in Science & Mathematics ➔ Mathematics
Basially, what this means is that, everywhere in the function you see 'x' you replace it by 'a-2'
So,
f(x) = 5x² - 11
so, f(a-2) = 5(a-2)² - 11
f(a-2) = 5(a²-4a+4) - 11
f(a-2) = 5a² - 20a + 20 - 11
f(a-2) = 5a² - 20a + 9
2007-07-13 17:56:53 · answer #1 · answered by thugster17 2 · 0⤊ 0⤋
Substitution. f(a-2) = 5(a-2)^2 - 11 = 5(a*2 -4a +4) - 11 = 5a^2 -20a +9.
2007-07-13 17:47:52 · answer #2 · answered by Anonymous · 0⤊ 0⤋
f(a-2) = 5(a-2)^2-11
2007-07-13 17:46:49 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋
f(a - 2) = 5 (a - 2)² - 11
f(a - 2) = 5 (a² - 4 a + 4) - 11
f(a - 2) = 5 a² - 20 a + 9
2007-07-13 19:47:05 · answer #4 · answered by Como 7 · 0⤊ 0⤋
Substitute x in the original equation with (a-2)
So, we get,
f(a-2) = [5(a-2)^2] - 11
f(a-2) = [5(a^2 -2a + 4)] - 11
f(a-2) = 5a^2 - 10a + 20 - 11
f(a-2) = 5a^2 - 10a + 9 ......... ANS
hope this helps!! :-)
2007-07-13 17:47:51 · answer #5 · answered by Sindhoor 2 · 1⤊ 0⤋
replace x with (a-2)
2007-07-13 17:51:11 · answer #6 · answered by qwert 5 · 0⤊ 0⤋