English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories
1

A plane took 1 hour longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, what was the flying time for the second part of the trip? Set up an equation and solve.

2007-07-13 17:26:29 · 6 answers · asked by cw21 1 in Science & Mathematics Mathematics

6 answers

560 miles - x + 1 hrs
480 miles - x hrs

speed = distance/time

But speed is the same for both portions, so,

560/(x+1) = 480/x

560x = 480x + 480
80x = 480
x = 6 hrs.

Flying time for the second part = 6 hrs

2007-07-13 17:32:14 · answer #1 · answered by Anonymous · 1 0

Second portion of flight:
time(T) = t+1 hours
distance(D) = 560 miles
speed (S) = distance / time.... (formulae for speed)

First portion of flight:
time(T) = t hours
distance(D) = 480 miles
speed = distance / time....

Because the speed was same for the first and second portion, we can equate the equations like.
speed 1 = speed 2
thus,
560 / (t+1) = 480 / t
Taking the LCM and making the denominator same,
560t / (t(t+1) = 480(t+1) / (t(t+1))
The denominator from both sides cancell out to be,
560t = 480t + 480
560t - 480t = 480
80t = 480
t = 480 / 80
t = 6 ............ this was the time taken to complete the first portion of the journey (in hours)

the second part of the journey took one more hour, so,
the second portion of the journey took 7 hours to complete

hope this helps!! :-)

2007-07-13 17:39:47 · answer #2 · answered by Sindhoor 2 · 0 0

let t be the time on the second portion, then t + 1 is the time on the first portion

distance = speed * time

the speeds on the portions are the same. Let v be the speed
560 = v(t + 1)
480 = vt

solve for t
t = 480/v
560 = v (480/v + 1)
560 = 480 + v
80 = v


plug the speed in
560 = 80 (t + 1)
7 = t + 1
t = 6

it takes 6hrs on the second portion

2007-07-13 17:36:37 · answer #3 · answered by      7 · 0 0

First Part:
time = t , d = 560 , speed = 560 / t

Second Part:
time = (t - 1) , d = 480 , speed = 480 / (t - 1)

560 / t = 480 / (t - 1)
560 (t - 1) = 480 t
560 t - 560 = 480 t
80 t = 560
t = 7

Time for second part = 6 hours

2007-07-13 22:47:34 · answer #4 · answered by Como 7 · 0 0

Mental math approach:
v = (560-480)/1 = 80 mph
t = 480/80 = 6 h, for the second part of the trip.

2007-07-13 17:34:28 · answer #5 · answered by sahsjing 7 · 0 1

Since the velocity was constant, you can simply subtract. 560 miles-480 miles in one more hour. Or 60 miles/hour
Since they are going 60 miles per hour, the second leg takes 480 miles/60 miles per hour or 6 hours as stated above.

2007-07-13 17:43:18 · answer #6 · answered by gordonmorrison 6 · 0 0

fedest.com, questions and answers