Reduce your answer to lowest terms
((1)/(t-2))+((3)/t))
2007-07-13 17:09:32 · 3 answers · asked by how you doin 1 in Science & Mathematics ➔ Mathematics
1/(t-2) + 3/t
= t/t(t-2) + 3(t-2)/t(t-2)
=(t+3t-6))/t(t-2)
=(4t-6)/t(t-2)
=2(2t-3)/t(t-2) ....... answer
Good luck.
2007-07-13 17:12:08 · answer #1 · answered by de4th 4 · 0⤊ 0⤋
I suppose you want to do this addition
So convert the denominators to LCD form
and [t(1) + (t-2)3]/ [ t (t-2)] = 4t-6/[t (t-2)]
Simplifying slightly 2 (t-3) /[t (t-2) ]
2007-07-14 00:15:38 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
[1/ (t-2)] + [3 / t]
to make the base common, take LCM,
which will be t(t-2)
[t / (t(t-2))] + [(3(t-2)) / (t(t-2))]
Since the denominators are the same we can have simple addition on the numerators,
[t + (3(t-2))] / [t(t-2)]
[t + 3t - 6] / [t(t-2)]
(4t - 6) / (t^2 - 2t) ............ ANS
hope this helps!! :-)
2007-07-14 00:16:45 · answer #3 · answered by Sindhoor 2 · 0⤊ 0⤋