How do you solve y using elimination method?

Question

2x - 2y = -4
-2x + 3y = 12

Answer 1

You add the two equations together.

That will "eliminate" the x's

2x -2x -2y + 3y = 12 -4

3y - 2y = 8
y = 8

Answer 2

add the 2 equations that eliminate the x leaving the value of y:
2x - 2y = -4
-2x + 3y = 12

0 + y = 8
y=8

then substituting the value of y to the first equation solving for x:
2x - 2y = -4
2x - 28 = -4
2x = -4+28
2x = 24
x=12

Answer 3

I get back to you once i review my algebra notes. My memory needs to refresh. For now consider this solution:

2x - 2y = -4
(+) -2x + 3y = 12
________________
y = 8

Answer 4

elimination method means you "remove" the other variable so you can solve for the variable you want to.
In your example, you simply ADD the equations:
2x - 2y = -4
-2x + 3y = 12
-------------------
y = 8
But in cases where you cannot simply add to eliminate, you first multiply both equations by a number (one for each equation) that will yield to the same coefficient for the variable you desire to be eliminated (i.e, their Least Common Multiple - LCM)

Answer 5

2x - 2y = -4...........(1)
-2x + 3y =12...........(2)
Add (1) + (2)
y = 8......Ans
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Answer 6

y = 8

x = 6

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