help me please?

1 ⤊

[1/2 (cos pi/10+ i sin pi/10]^5

2007-07-13 12:08:29 · 3 answers · asked by jessie0420 2 in Science & Mathematics ➔ Mathematics

3 answers

[1/2 (cos pi/10+ i sin pi/10]^5
= (1/32)e^(i*pi/2)
= i/32

2007-07-13 12:25:42 · answer #1 · answered by sahsjing 7 · 1⤊ 0⤋

Hi,

If I type [1/2 (cos pi/10+ i sin pi/10]^5 into my TI83, it gives me
-.0566856206 + .0150966605i.

I hope that helps!! :-)

2007-07-13 19:42:14 · answer #2 · answered by Pi R Squared 7 · 0⤊ 2⤋

[1/32 change rectangular to polar to raise to 5th power]
1/32 * (1 angle pi/10 )^5
1/32 *(1 angle 1.5707)
convert back to rectangular to get
1/32* (0,1)

2007-07-13 19:33:17 · answer #3 · answered by 037 G 6 · 0⤊ 0⤋