A horse's feed requires both hay and oats, and a horse weighing 980 pounds requires 21.6 pounds of feed a day. The ratio of hay to oats is 17:3. How many pounds of oats does a horse need in a day?
2007-07-13 11:33:14 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Break down the ratio... 17 parts hay and 3 parts oats, for a whole of 20.
So, 3/20 is the total part of oats for each pound of fee.
If the horse eats 21.6 pounds of feed, then 3/20 * 21.6 = 3.24 total pounds of oats a horse needs per day.
2007-07-13 11:43:05 · answer #1 · answered by Andrew K 2 · 0⤊ 0⤋
From the ratio of hay to oats 17:3,
total amount of feed is 17+3=20 in ratio.
So, amount of oats is 3/20 in ratio.
3/20 of the pounds of feed 21.6 is the pounds of oats.
thus,
21.6*3/20=3.24
The horse need 3.24 pounds of oats in a day.
2007-07-13 19:05:21 · answer #2 · answered by Motohiro T 1 · 0⤊ 0⤋
Let
X = # of pounds (of hay)
Y = # of pounds (of Oats)
ratio of hay to oats is 17:3 means
X/Y = 17/3
so,
X = (17/3) Y
a horse requires 21.6 pounds of feed a day means
(# of pounds of oats) + (# of pounds of hays) = 21.6
X + Y = 21.6
Substitue X = (17/3) Y into
X + Y = 21.6
(17/3) Y + Y = 21.6
solve for Y
Y = 3.24 pounds <== # of pounds of oats
2007-07-13 18:48:36 · answer #3 · answered by buoisang 4 · 0⤊ 0⤋
17:3 is a total of 17+3 parts or 20.
since 3/20 is oats times the total of 21.6 is 3.24 lb oats per day the rest is hay 18.36 lb
2007-07-13 18:44:37 · answer #4 · answered by 037 G 6 · 0⤊ 0⤋
20x = 21.6
x = 1.08
3x = 3.24 pounds of oats
17x = =18.36 pound of hay
2007-07-13 18:47:14 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋