First pick seven values for example x like -3, -2, -1, 0,1,2, 3 and make an x and y table then begin plugging the values into the equations for example for the equation y = |x| +2 pick the first value plug it in for x and solve then do the same for all the other values as you will find that both equations are getting the same values at the points (0,2) (1,3) (-1,3) so both equations do work.
2007-07-13 08:03:01
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answer #1
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answered by i love field hockey 1
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You can't determine that from here. You need another point because you use (-1,3) and (1,3) which, since both equations are symmetric (even functions), does not help you, so you are really only using 2 points! unless you are given information about the slope of the function, then you're out of luck, both will pass through these points.
2007-07-13 15:00:55
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answer #2
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answered by Anonymous
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Sure. You just showed it
Actually it is the intersection of a parabola and two lines in the shape of a V. The vertex of the V and the vertex of the parabola are 0ne 0f the common points (0,2) , and the intersection of each line with the parabola are the other two points ((1,3) and (-1,3).
2007-07-13 15:00:43
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answer #3
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answered by ironduke8159 7
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Just plug the points in and check:
(0,2): both
(1,3): both
(-1, 3): both
So yes, both eqns are possible.
2007-07-13 14:49:31
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answer #4
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answered by miggitymaggz 5
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I'm not here to do your homework...
2007-07-13 14:48:43
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answer #5
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answered by Sara+H 2
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