x^2/x-3 minus 9/x-3?

Question

I am confused on the steps can u please help me. I am sure it is more simple then I am making it but I am terrible at math.

Answer 1

x^2/x-3 - 9/x-3
(x^2-9) /x-3
(x+3)(x-3) /x-3
=x+3

Answer 2

x+3

Answer 3

x^2 / (x - 3) - 9/(x - 3)

since the denominators are the same, subtract the numerator

(x^2 - 9) / (x - 3)

the expression on the numerator is the difference of perfect square. use this formula
a^2 - b^2 = (a - b) (a + b)

(x^2 - 3^2) / (x - 3)

(x - 3) (x + 3) / (x - 3)

simplify, (x - 3) cancels out, leaving you with x + 3

Answer 4

x^2/(x-3) - 9/(x-3) =
(x^2-9)/(x-3)=
((x+3)(x-3)/(x-3))=
x+3

In these kind of problems just try with say x=1
to see if it is correct. Put x=1 in the top expression
1^2/(1-3)-9/(1-3)=-1/2+9/2=
8/2=4 and the answer is x+3;
1+3=4

Answer 5

Example
A / (x - 3) - B / (x - 3) = (A - B) / (x - 3)
thus
(x²) / (x - 3) - 9 / (x - 3) = (x² - 9) / (x - 3)
Which can be simplified as follows:-
(x - 3)(x + 3) / (x - 3) = x + 3

Answer 6

You can put it in one fraction like this (x^2-9)/(x-3)

Then factor (x^2-9) to get (x+3)(x-3)/(x-3)

Cancel out the (x-3) to get the answer which is:

x+3

Answer 7

Because the denomenators are the same, right it as:

x^2 - 9
---------
x - 3

Now factor the numerator and write it out as:

(x + 3)(x - 3)
----------------
(x - 3)

Because there is a (x-3) on the top and bottom, we can eliminate these, leaving us with:

x + 3

Answer 8

All the above answers are correct, except they all failed to indicate that x cannot =3. This qualification is necessary to accurately state the solution.