sorry this is the one I had issues with?
2007-07-13 07:31:06 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x^2 – x- 3/3x^2 + 7x +4)* (3x^2 – 11x -20/ 4x^2 -9)
(x+1)(2x-3) / (x+1)(3x+4) * (3x+4)(x-5) / (2x+3)(2x-3)
solving we get
x-5 / 2x+3
2007-07-13 07:37:17 · answer #1 · answered by sweet n simple 5 · 0⤊ 1⤋
As you have presented it,
2x^2 – x- 3/3x^2 + 7x +4 times 3x^2 – 11x -20/ 4x^2 -9
becomes
2x^2 - x - 1/x^2 + 7x + 12x^2 - 11x - 5/x^2 - 9 =
14x^2 - 5x - 6/x^2 - 9
which, I'm sure, is not the answer you're looking for.
It really isn't all that difficult to learn the use of parentheses.
2007-07-13 08:07:20 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
chuffed Belated New 12 months! :) I confident wish all is definitely. :) As on your question, right it incredibly is my attempt to interrupt down the answer for you. :) The regulations of fractions in Math dictate that, while fraction a/b is split by yet another fraction, c/d, the 2nd fraction is inverted then larger by the 1st fraction. which means: a/b / c/d = a/b * d/c So, the answer on your question may be: [2X^2 -- x -- 3] ---------------------- / [3X^2 -- 7X + 4] [2X^2 + X -- 6] ----------------------- = [3X^2 + 2X -- 8] [2X^2 -- x -- 3] ---------------------- * [3X^2 -- 7X + 4] [3X^2 + 2X -- 8] ---------------------- = [2X^2 + X -- 6] next, we ingredient each thing to simplify. That leads to: [(2X + 3)(X -- a million)] ----------------------- * [(3X -- 4)(X -- a million)] [(3X -- 4)(X + 2)] ----------------------- = [(2X -- 3)(X + 2)] (2X + 3) ------------ (2X -- 3) i attempted putting all the fractions on one line, yet they stored popping out scrambled, and so it wasn't sparkling what grow to be being divided by what and what grow to be being larger by what. Too undesirable approximately that. i'm hoping that grow to be sparkling adequate for you and that it enables, in basic terms the comparable. :) I did my terrific besides. :) stable success, take care and characteristic an incredible day. :) Cheers! :)
2016-12-10 11:10:25 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Clean up your expression by adding similar terms together. Then each term of the first expression has to be multiplied with every term in the second expression. After this clean up again, and group similar terms together. Give it a try.
2007-07-13 07:36:29 · answer #4 · answered by Mr P 1 · 1⤊ 0⤋
rewrite your question with some brackets () is it 2x^2 or 2x^2-x? ... it's a little hard to see where the breaks are, and what goes together.
2007-07-13 07:35:07 · answer #5 · answered by Tony M 2 · 1⤊ 0⤋
wat is the X
2007-07-13 07:39:17 · answer #6 · answered by BlackIce Mikel 3 · 0⤊ 1⤋