How many grams of water is required to be mixed with 11.75 grams HgCl in order to make a 0.01 m solution?

Question

Refer to the periodic table for atomic weights.
Please help me with this question on showing me how to work it out and find it. Please and thank you for anyone who decides to help.

Answer 1

Since molality is measured in moles solute per kg of solvent, you have to first change the HgCl to moles. Divide 11.75 by the molar mass, 236.04 g. You end up with 0.04978 moles. That number of moles divided by one kg of water is equal to 0.1 molar. (0.04978 mol/x kg = 0.1 m)
Simple algebra leaves you with 0.4978 kg, or 497.8 grams of water.
I hope that helps.

Answer 2

361