Solve the following equation for x .square root x^2-9=4?

Answer 1

square root( x^2-9)=4
=> x^2 - 9 = 16
=> x^2 - 25 =0
=> (x+5)(x-5)=0
=> x=5 or x=-5
check ans
both work

Answer 2

Add 9 to both sides:

x^2 = 4 + 9

x ^2 = 13

x = square root of 13

Answer 3

x = +5, -5

objective is to get rid of the radical sign froom the the left side of the equation. Inorder to do that yu have to square both sides which results in

x^2-9= (4)^2. (16)

then you add 9 to both sides to get x^2=25.

inorder to isolate the x you have to square root both sides and you are left with x. when you rad a number x becomes a positive and a negative so..

-5, and 5

Answer 4

x^2 - 9 = 4

x^-9+9 = 4 +9

x^2 = 13

Get square root of both sides

x = Square root of 13

x = 3.60555

Answer 5

I will assume you mean sqrt(x^2-9)=4
You want to get x by itself. Since it is traped by the sqrt, square both sides to give you x^2-9=16
then add 9 to both sides x^2=25
then take the sqrt of both sides
x = -5, 5

Answer 6

so x^2-9=4^2
or x^2-9=16
or x^2-25=0
or (x-5)(x+5)=0
x=5 or x=-5 ans

Answer 7

y=3x-a million xsquared + ysquared = 40 substiute first equation into 2d equation as y you get:- xsquared + (3x-a million)squared = 40 10xsquared-6x+a million=40 10xsquared-6x-39=0 and then in basic terms factorise, get values for x and replace x -values into first equation to get y-values.

Answer 8

(x² - 9)^(1/2) = 4
x² - 9 = 16
x² = 25
x = ± 5

Answer 9

x^2=13 its whatever the sqare root of 13 is

somewhere around 3.605...i think (i dont know i may have gotten the entire thing wrong)