I solved it and the answer was 0 <4. Is that considered an infinite number of solutions or no solution at all. When do you consider an inequality to be no solution? The only thing that I could think of involves absolute value but that is not what i'm asking here.
2007-07-12 22:23:53 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
since 0 is less than four, the statement's true so it's infinite solutions. if it would've been false it would've been no solution
2007-07-12 22:43:58 · answer #1 · answered by Anonymous · 0⤊ 0⤋
4(3x-2) - 3x < 3(1+3x) - 7
first, expand the stuff inside the parentheses using the distribution property:
12x - 8 - 3x < 3 + 9x - 7
simplify:
9x - 8 < 9x - 4
-8 < -4
as you can see, even if you manipulate the last inequality, the truth or correctness of the statement would remain. in cases like this, you may conclude that for any real number x, the statement will always be true.
therefore x = set of all real numbers
2007-07-17 08:07:22 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Did you ask the previous question? Have you selected a "best answer"? Well, for this one.
4(3x - 2) - 3x < 3(1 + 3x) - 7
12x - 8 -3x < 3 + 9x - 7
9x - 8 < 9x - 4
therefore 0 < 4
No, absolute values are not the answer. As you know, zero is less than 4 so that is your answer.
2007-07-13 05:42:48 · answer #3 · answered by jemhasb 7 · 0⤊ 0⤋
On solving
4(3x - 2) - 3x < 3(1 + 3x) - 7
12x - 8 -3x < 3 + 9x - 7
9x - 8 < 9x - 4
0<4
Now, what we need to do is little rational thinking.
We all know
0<4 is true
add 9x on both side
(MATHS RULE:: you are allowed to add/substract same amount on both sides of a inequality)
9x<4+9x is true
which is same as
9x-8<9x+3-7 is true
which is same as
12x - 8 -3x < 3 + 9x - 7 is true
4(3x - 2) - 3x < 3(1 + 3x) - 7 is true
Whenever a mathematical expression in x (ie with a variable) comes out to be TRUE its called a IDENTITY.
Hence the inequality is a IDENTITY.
Examples:
~ 7x+6>6x+5+x
~ (a+b)^2=a^2 +b^2 +2ab
~ (a+b)(a-b)=a^2-b^2
2007-07-13 06:58:16 · answer #4 · answered by Prateek 2 · 1⤊ 1⤋
the solution is all numbers less than 0
2007-07-13 05:28:19 · answer #5 · answered by Anonymous · 0⤊ 0⤋
It means it's faulse. Never 0<4.
2007-07-13 05:29:35 · answer #6 · answered by DreamGirl 4 · 0⤊ 0⤋
see im doing it for ya..see and learn frm me...
4(3x-2) - 3x < 3(1+3x) - 7
12x-8-3x < 3+9x-7
9x-8 < -4+9x
-8+4 < -9x+9x
4 < 0
yeah dude ur wrong...!!! how is it possible...
tc
2007-07-13 05:42:03 · answer #7 · answered by d_champz_here 2 · 0⤊ 0⤋