Find a positive value of the given variable so that the trinomial is factorable.
5x2 + 8x + c; c = ?
8
9
3
4
2007-07-12 20:14:58 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5x2 + 8x + c
( 5x + 3)( x + 1) =0
c= 3
since we have ax+by+c=0 and u say that a=5. the only way is 5*1=5
how to make 8? we can only do it with 5+3=8
so,the answer is 3
if not believe,try expand the equation and u will get it correct
2007-07-12 20:20:47 · answer #1 · answered by Clov 2 · 0⤊ 0⤋
5x2 + 8x + c
5x^2 + 5x + 3x + c
5x^2 + 5x + 3x + 3
5 x(x + 1) + 1( x + 1)
(5x + 1)(x + 1)
so the equation is factorable only when c = 3
2007-07-13 04:14:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(x + 1) (5x + 3) so c = 3
2007-07-13 04:07:31 · answer #3 · answered by Como 7 · 0⤊ 0⤋
Gosh I'm glad I'm no longer in school.
Hope this helps!
2007-07-13 03:18:37 · answer #4 · answered by Just_One_Man's_Opinion 5 · 1⤊ 1⤋