The width of the field is 200 feet less than its width? I don't even know what that means, so I'm going to go ahead and assume you meant that the width is 200 feet less than the LENGTH.
l = length, w = width
P = 2l + 2w 2l = P - 2w
and we know that l = w + 200
Thus, P = 2(w + 200) + 2w
P=2w + 400 + 2w
P= 4w + 400
4w = P - 400
w = P/4 - 100
finally
l = w + 200 = P/4 + 100
I hope you understood that.
2007-07-12 18:24:55
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answer #1
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answered by wolfey6 2
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Let P = the perimeter of the rectangle.
Let L = the length of the rectangle.
Let W = the width of the rectangle.
Since L will be 200 feet longer than the width,
Ergo, L = W + 200
Based on common knowledge, the perimeter of a rectangle is the total length of all four sides.
Since there are two equal widths and two equal lengths, the
perimeter formula is:
P = 2L + 2W
substituting our definition at the beginning that
L = W + 200,
then, P = 2(W+200) + 2W
P = 2w + 400 + 2 W
P = 4w + 400
w= (P- 400)/4
Now that we know the value of W in terms of P, we
can compute the value of L as required by your problem:
L = w + 200
substituting our W value into the equation,
L = (P -400)/4 + 200 THE ANSWER
This indeed is the "length" of the required solution to your problem. You have a great, blessed evening! (Hopefully,
in a bed with adequate "width").
2007-07-13 01:46:04
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answer #2
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answered by the lion and the bee 3
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First, I think you meant that the width of the field is 200 ft less than its width.
a) let L = length of field
the W = width of field. Note that
W = L - 200.
b) Perimeter P = 2L + 2W (the length around the field)
= 2L + 2(L-200) or
P = 2L +2L -400, or
P = 4L - 400. So,
4L = P + 400 or
L = P/4 + 100
2007-07-13 01:16:46
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answer #3
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answered by pbb1001 5
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The general formula is P = 2L + 2W Your info says that ... um. I see a typo. I will assume you meant "The width of the field is 200 feet less than its length." So you said that W=L-200. So by substitution, now P = 2L + 2(L-200) or P = 4L - 400. To get L alone you want to add 400 to both sides, then divide both sides by 4, thus... L = (P+400)/4
2007-07-13 01:16:04
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answer #4
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answered by LaWeezel 4
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P = 2w + 2L
w = L - 200
P = 2(L - 200) + 2L
P = 2L - 400 + 2L
P = 4L - 400
P + 400 = 4L
P/4 + 400/4 = L
L = P/4 + 100
2007-07-13 01:17:37
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answer #5
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answered by Anonymous
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Let sides be x and x - 200
P = 2x + 2(x - 200)
P = 4x - 400
4x = P + 400
x = P/4 + 100
Sides are P/4 + 100 ft and P/4 - 100 ft
2007-07-13 03:52:45
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answer #6
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answered by Como 7
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P=2W+2L
W=L-200 it's given,though, you stated it incorrectly.
P=2(L-200) + 2L
P= 2L-400+2L
P= 4L-400 add +400 to both sides of the equation
P+400=4L-400+400
P+400=4L divide both sides by 4
L=P+400/4
2007-07-13 01:51:35
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answer #7
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answered by Anonymous
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Width is 200 feet less than its length, therefore,
B=L-200
P=2(L+B)
P=2(L+L-200)
P=4L-400
L=(P+400)/4 feet
2007-07-13 01:15:32
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answer #8
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answered by Jain 4
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w the width
l the length
p=2w+2l
p=2(l-200)+2l
p=4l-400
l=(p+400)/4
l=p/4+100
2007-07-13 01:20:33
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answer #9
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answered by zohair 2
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you need 2 restate the ? and give more information
2007-07-13 01:16:33
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answer #10
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answered by RobertS 1
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