Foiling a cubed function?

Question

I always have a hard time foiling cubed functions:
For example (2+h)^3

Can anyone show me a process on how to do these kind of problems.

Answer 1

Sometimes I hate the FOIL process.. this is one of those times, since you can't really FOIL.

Break it up into three separate binomials:

(2 + h)(2 + h)(2 + h)

FOIL the first two terms:

(4 + 4h + h^2)(2+h)

Now multiply each of the terms in the trinomial by both of the terms in the binomial:

8 + 4h + 8h + 4h^2 + 2h^2 +h^3

Combine like terms and rearrange:

h^3 + 6h^3 + 12h +8

That should do it for you!

Answer 2

This Site Might Help You.

RE:
Foiling a cubed function?
I always have a hard time foiling cubed functions:
For example (2+h)^3

Can anyone show me a process on how to do these kind of problems.

Answer 3

You can use Pascal's triangle

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1

Each successive row contains the coefficients for the expansion of the next higher power n, of (x + y)^n. For n = 3 the coefficients are 1 3 3 1.

(2 + h)³ = 1*2³ + 3*2²h + 3*2h² + 1h³ = 8 + 12h + 6h² + h³

These coefficients can also be found as:

(3C3) (3C2) (3C1) (3C0) = 1 3 3 1

Answer 4

For the best answers, search on this site https://shorturl.im/avoeH

f(x)^3 =f(x)^2*f(x) So let's find the function squared and then multiply by the function again to get the function cubed. Using the foil method... (2t^2 + 2t +1/t)(2t^2 + 2t +1/t) is 2t^2(2t^2 + 2t +1/t)+... 2t(2t^2 + 2t +1/t)+... 1/t(2t^2 + 2t +1/t) =4t^4+4t^3+2t+4t^3+4t^2+2+2t+2+1/t^2 =4t^4+8t^3+4t^2+4^t+4+1/t^2 This is the function square. To get the function cubed we multiply by the function again... (4t^4+8t^3+4t^2+4^t+4+1/t^2)(2t^2 + 2t +1/t) Using the foil method this is... 2t^2(4t^4+8t^3+4t^2+4^t+4+1/t^2)+ 2t(4t^4+8t^3+4t^2+4^t+4+1/t^2)+ 1/t(4t^4+8t^3+4t^2+4^t+4+1/t^2) =8t^6+16t^5+8t^4+4t^3+4t^2+2+ 8t^5+16t^4+8t^3+8t^2+8t+2/t+ 4t^3+8t^2+4t+4+4/t+1/t^3 Collect like terms and the answer is: 8t^6+24t^5+24t^4+16t^3+20t^2+12^t+6+6/...

Answer 5

I always use piramid numbering
1
121
1331
14641
and so on.

Answer 6

(a+b)^3=a^3+b^3+3ab(a+b)

(2+h)^3=8+h^3+6h(2+h)
=8+h^3+12h+6h^2
=h^3+6h^2+12h+8