2007-07-12 16:53:17 · 10 answers · asked by lets.dancex3 1 in Science & Mathematics ➔ Mathematics
(2x+1)(x+2) = 5
2x^2 +x+4x+2=5
2x^2 +5x -3=0
(x+3)(2x - 1)=0
x= -3 or 1/2
2007-07-12 16:55:52 · answer #1 · answered by sweet n simple 5 · 0⤊ 0⤋
2 X 2 5
2016-12-16 19:18:41 · answer #2 · answered by camargo 4 · 0⤊ 0⤋
2x+1 = 5 / (x+2)
(2x+1)(x+2) = 5
2x^2 + 5x + 2 = 5
2x^2 +5x -3 = 0
(2x-1)(x+3) = 0
x = 1/2, -3
2007-07-12 16:57:17 · answer #3 · answered by Steve A 7 · 0⤊ 0⤋
(2x + 1) = 5 / (x + 2)
(x + 2)(2x + 1) = 5
2x^2 + 5x +2 = 5
2x^2 + 5x - 3 = 0
(2x - 1)(x + 3) = 0
So x = 1/2 or x = -3
2007-07-12 16:57:17 · answer #4 · answered by Reese 4 · 0⤊ 0⤋
2x+1= 5 / (x+2)
(2x+1)(x+2)=5
2x+1=5 or x+2=5
2x=4 or x=3
x=2 or 3.
2007-07-12 17:43:47 · answer #5 · answered by Kenneth Koh 5 · 0⤊ 0⤋
(2x + 1) (x + 2) = 5
2x² + 5x + 2 = 5
2x² + 5x - 3 = 0
(2x - 1) (x + 3) = 0
x = 1 / 2 , x = - 3
2007-07-12 21:00:52 · answer #6 · answered by Como 7 · 0⤊ 0⤋
(2x + 1) = 5 / (x + 2)
or, (2x+1)(x+2) = 5
or, 2x^2 +x+4x+2=5
or,2x^2 +5x -3=0
or, (x+3)(2x - 1)=0
therefore
either x = -3
or x = 1/2
2007-07-12 17:25:23 · answer #7 · answered by looja bajra 1 · 0⤊ 0⤋
x = -3
2007-07-12 16:56:58 · answer #8 · answered by ☺ . CIEL . ☺ 5 · 0⤊ 0⤋
(2x+1)(x+2)=5
2x^2+5x+2=5
2x^2+5x-3=0
2007-07-12 16:59:43 · answer #9 · answered by deva 2 · 0⤊ 0⤋
-3
2007-07-12 17:16:54 · answer #10 · answered by pitcheer358 2 · 0⤊ 0⤋