2007-07-12 16:31:04 · 6 answers · asked by none 1 in Science & Mathematics ➔ Mathematics
27, the triangles points are at (-3, 5), (-3, -1), and (6, -1).
the base is 9 and height is 6.
Area of a triangle = 1/2 (base x height)
1/2 (9 x 6)
1/2 (54)
27
2007-07-12 16:39:12 · answer #1 · answered by spares1080 2 · 0⤊ 0⤋
Find the intercept points of these 3 lines.
x= -3 ...(1)
y= -1 ...(2)
y=(-2/3)x + 3 ...(3)
Solve (1) and (3): When x = -3, y = 5.
Solve (2) and (3): When y = -1, x = 6.
Intercept point of line (1) and (2) at x = -3, y = -1.
Use area formula or
draw these points on coordinate which shows right triangle with base 9 unit and height 6 unit.
So the area is 27 square units
2007-07-12 23:46:31 · answer #2 · answered by cllau74 4 · 0⤊ 0⤋
First, solve for where y = -(2/3)x + 3 meets x = -3:
y = -(2/3)*(-3) + 3
y = 5
Next, solve for where y = -(2/3)x + 3 meets y = -1
-1 = -(2/3)x + 3
4 = (2/3)x
x = 6
The base of the triangle is (6 - (-3)) = 9, and the height is (5 - (-1)) = 6
Area = Base * Height / 2 = 27 square units.
2007-07-12 23:39:35 · answer #3 · answered by Andrew D 1 · 0⤊ 0⤋
Line 1: x = - 3
Line 2: y = - 1
Line 3: y = ( - 2/3 ) x + 3
Line 1 and line 2 intersect at (-3 , - 1)
Line 1 and line 3 intersect at (-3 , 5)
Line 2 and line 3 intersect at (6 , - 1)
Base of triangle is length 9
Height of traingle is length 6
Area = 1/2 x 9 x 6 units²
Area = 27 units²
2007-07-13 02:42:26 · answer #4 · answered by Como 7 · 0⤊ 0⤋
What exactly are you asking?
2007-07-12 23:35:46 · answer #5 · answered by N C 1 · 0⤊ 0⤋
he is asking for help
2007-07-12 23:38:24 · answer #6 · answered by ۞_ʞɾ_ 6 · 0⤊ 0⤋