if a cylinder has 6.3 diameter, height of 16.2 and a density of 22.5 what is it weight?

Answer 1

Volume of a cylinder equals pi, times one half the diameter, squared, times height. Volume = 3.14 x (0.5 x 6.3)^2 x 16.2 = 504.7 cubic units.

Weight would be the volume times the density = 504.7 x 22.5 = about 11,300. This assumes that density is also measured per cubic unit.

Answer 2

No units?

If the density of 22.5 is g/cm^3 and the diameter and height are also in cm, then figure as below. Or if the density is in cubic meters and the measurements are in meters, it's ok. Any unit that matches. Otherwise, you'll have more conversion to do.

Find the volume in cubic units.
Volume of a cylinder is area of the base times the height.
Area of the base is pi times the radius squared = 3.14*3.15*3.15
multiplied by the height = 504.74 cubic units

504.74 cubic units * 22.5 mass units/cubic unit = 11356.65 mass units (grams or whatever)

Answer 3

dia is 6.3 so radius is 6.3/2 =3.15

from the given height 16.2 volume of the cylinder can be calculated from the formula pi*square of The radius*height

=3.1415*3.15*3.15*16.2
=504.978 cubic unit

now density= weight/volume

you know th volume and density
you can calculate weight
as 504.978*22.5
=11362.02

you didn't provide any unit????
so if i consider standard unit
the answer is also in standard unit KG

Answer 4

3.15 x 3.15 x 3.14 x 16.2= 504.8 units³
D = m/v
D = m/504.8
m = 22.5/504.8 = 0.045 x 9.81 = 0.437 N weight.