At Gwen's garage sale, all books were one price while all magazines were another. Joe bought 4 books and 3 magazines for $1.45 and Jane bought 2 books and 5 magazines for $1.25. What was the price of a book and what was the price of a magazine?
2007-07-12 15:41:14 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
books are 25 cents
magazines are 15 cents
2007-07-12 15:46:05 · answer #1 · answered by josh e 2 · 1⤊ 1⤋
let cost of a book be x cents and that of a magazine be y cents.
4x + 3y = 145 ..... (1)
2x + 5y = 125 ..... (2)
(2) * 2 -----> 4x + 10y = 250 ..... (3)
Subtract (1) from (3),
4x - 4x + 10y - 3y = 250 - 145
7y = 105
y = 15
Put y = 15 in (2),
2x + 75 = 125
2x = 50
x = 25
x = 25, y = 15
The price of a book is 25 cents and the price of a magazine is 15 cents
2007-07-15 09:34:40 · answer #2 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
book = 25 cents
magazine = 15 cents
2007-07-12 23:36:05 · answer #3 · answered by chand 1 · 0⤊ 1⤋
book = 25 cents
magazine = 15 cents
2007-07-12 22:47:09 · answer #4 · answered by Anonymous · 0⤊ 1⤋
Let the price of 1 book be $b and the price of 1 magazine be $m.
4b+3m=1.45 -----(1)
2b+5m=1.25 -----(2)
(2)x2
4b+10m=2.50 ----(3)
(3) - (1)
7m= 1.05
m = 0.15
b = 0.25
2007-07-12 22:48:41 · answer #5 · answered by iyiem 2 · 0⤊ 1⤋
(1) 4b + 3m = 1.45
(2) 2b + 5m = 1.25
Multiply (1) by -1 and (2) by 2 and sum:
-4b - 3m = -1.45
4b + 10m = 2.50
------------------------
7m = 1.05
m = .15
Substitute .15 for m throughout, and solve for b. b = .25
Books are 25 cents, magazines are 15 cents.
2007-07-12 22:47:44 · answer #6 · answered by Andrew D 1 · 0⤊ 1⤋
4b + 3m = 1.45
2b + 5m = 1.25 ==> 4b + 10m = 2.50, or
7m = 1.05, so m = .15, and therefore b = .25
2007-07-12 22:46:34 · answer #7 · answered by John V 6 · 1⤊ 1⤋
4x+3y = 1.45 ... (1)
2x+5y = 1.25 ... (2)
(2)x2 - (1) : y = 0.15, x = 0.25
2007-07-12 22:46:25 · answer #8 · answered by cllau74 4 · 0⤊ 1⤋