Tickets for a concert were sold to adults for $3 and to students for $2. If the total receipts were $824 and twice as many adult tickets as student tickets were sold, then how many of each were sold?
2007-07-12 15:35:18 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
let x = number of students
then 2x = number of adults
3(2x) + 2(x) = 824
8x = 824
x = 103
there were 103 students and 206 adults
2007-07-12 15:39:27 · answer #1 · answered by TENBONG 3 · 0⤊ 1⤋
Let no. of students who attended be x
No. of adults = y
2x + 3y = 824 ..... (1)
y = 2x ..... (2)
Put (2) in (1),
2x + 6x = 824
8x = 824
x = 103
Put x = 103 in (2)
y = 2*103 = 206
x = 103, y = 206
103 student tickets and 206 adult tickets were sold.
2007-07-15 02:34:42 · answer #2 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
824 = 3a + 2s
a = 2s
824 = 3(2s) + 2s
824 = 8s
s = 103 student tickets
a = 2s = 206 adult tickets
2007-07-12 15:39:40 · answer #3 · answered by therealchuckbales 5 · 0⤊ 1⤋
let A = number of adults
let S = number of students
so the 2 equations u wud get are
3A + 2S =824
and S = 2A
then u cud solve the problem by substiuting the S in the first equation with the 2A.
2007-07-12 15:42:16 · answer #4 · answered by pwh 2 · 0⤊ 1⤋