Hey there!
Here's the answer.
10b-45=3(b-15) --> Write the problem.
10b-45=3b-45 --> Simplify the above equation.
10b=3b --> Add 45 on both sides of the equation.
7b=0 --> Subtract 3b on both sides of the equation.
b=0 --> Divide 7 on both sides of the equation.
So the answer is b=0.
Hope it helps!
2007-07-12 15:23:17
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answer #1
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answered by ? 6
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Hi, first you would want to follow the order of operations. PEMDAS.
10b-45=3(b-15) Take the 3 and multiply it by everything in that ( )
10b -45= 3b-45
Now add your like terms:
add 45 to the -45 that equals 0
Subtract the 3b from the 10b
Now you have this equation: 7b=0
Divide the 7 from both sides and you get:
b= 0
2007-07-12 15:16:10
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answer #2
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answered by Dogna M 4
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10b - 45 = 3(b-15)
10b-45 = 3*b - 3*15
10b - 45 = 3b -45
10b-45+45 = 3b-45+45
10b=3b
10b-3b = 3b-3b
7b = 0
7b/7 = 0/7
b = 0
2007-07-13 04:26:55
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answer #3
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answered by Anonymous
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10b - 45 = 3(b-15)
10b - 45 = 3b -45
10b - 3b = -45 + 45
7b = 0
b = 0
2007-07-12 15:16:42
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answer #4
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answered by Richard_CA 4
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10b - 45 = 3(b - 15)
10b - 45 = 3b - 45 <--at this point you can see something's up.
7b - 45 = -45
7b = 0
b = 0
2007-07-12 15:14:54
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answer #5
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answered by Anonymous
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10b - 45 = 3(b - 15)
= 3b - 45
Add 45 to both sides.
10b = 3b
Subtract 3b from both sides.
7b = 0
Divide both sides by 7
b = 0
2007-07-12 15:14:35
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answer #6
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answered by Michael 2
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10b - 45 = 3(b - 15)
10b - 45 = 3b - 45
10b - 3b - 45 = 3b -3b - 45
7b - 45 = -45
7b - 45 + 45 = -45 + 45
7b = 0
b = 0
2007-07-12 15:14:45
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answer #7
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answered by D J 3
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10b = 3b -45 + 45
10b = 3b which is not true, 10 does not = 3 , so b must be zero
2007-07-12 15:13:56
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answer #8
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answered by SleepyPlant 3
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10b - 45 = 3b - 45
10b - 3b = -45 + 45
7b = 0
b = 0
2007-07-12 15:19:24
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answer #9
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answered by nikkiwahine 2
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10b-45=3(b-15)
10b-45=3b-45
-3b+45=-3b+45
7b=0
b=0
2007-07-12 15:15:11
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answer #10
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answered by Dave 2
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