2007-07-12 12:18:41 · 6 answers · asked by Jose V 1 in Cars & Transportation ➔ Other - Cars & Transportation
4500 Newtons
2007-07-12 12:40:52 · answer #1 · answered by Rich 4 · 0⤊ 0⤋
F = ma is your toddler right here. For the 1st one, how lots weight would desire to the rotors elevate? they'd desire to elevate the load of the motor vehicle and the helicopter top? So we upload them jointly. 5000kg + 1500kg = 6500kg comprehensive that the rotors would desire to elevate. all of us recognize that the acceleration as a results of gravity is 9.81m/s2, however the helicopter is accelerating upwards at 0.6m/s2. If its accelerating up, its making the load "experience" like its heavier than it is. So we upload the accelerations. 9.eighty one + 0.6 = 10.41m/s2. Now basically replace into F = ma F = 6500kg * 10.41m/s2 = 67665 N For B, the rigidity interior the cable could basically be the stress of the motor vehicle top? Cuz the cable is basically conserving the motor vehicle up. So back F = ma F = 1500kg * 10.41m/s2 = 15615N
2016-11-09 03:59:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Force=mass x acceleration
2007-07-12 12:20:55 · answer #3 · answered by Del Piero 10 7 · 0⤊ 0⤋
F=ma
F=3.00*1500kg
F=4500N
F=4.5kN
2007-07-13 09:46:22 · answer #4 · answered by Anonymous · 0⤊ 0⤋
about 475 horse old school.
2007-07-12 14:19:36 · answer #5 · answered by Rusty R 3 · 0⤊ 0⤋
50 LB/FT of torque will keep it going.
2007-07-12 12:22:25 · answer #6 · answered by Anonymous · 0⤊ 0⤋