2007-07-12 11:43:59 · 4 answers · asked by CPUcate 6 in Science & Mathematics ➔ Mathematics
The other side is sqrt(20^2-4^2-6^2)=sqrt(348)
Vol=4 x 6 x sqrt(348)=447.7
2007-07-12 11:52:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋
if you are looking at the front of the box and width is 4 height is 6 and a diagonal from the a top corner to an opposite bottom corner is 20 then the depth is x and to solve for x we:
the front diagonal is squre root of 6^2+4^2=SQRT(52)
and 20^2= 52+x^2
400-52=x^2 x=sqrt 448= 21.166
The answer may change if the dimensions you gave are in another order ie depth=6 height=4 and length is x so please clarify for a better answer.
2007-07-12 12:14:25 · answer #2 · answered by 037 G 6 · 0⤊ 0⤋
H = sqrt(s1^2 +s2^2)
H = sqrt(14+36)
H = sqrt(50)
H = 7.071
2007-07-12 11:53:26 · answer #3 · answered by Anonymous · 0⤊ 0⤋
447.71
2007-07-12 11:55:27 · answer #4 · answered by Alberd 4 · 0⤊ 0⤋