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Reduce the following fraction to simplest terms.

x^2-49 / 7-x

2007-07-12 09:43:33 · 8 answers · asked by whatever ya want 1 in Science & Mathematics Mathematics

I don't have an algebra book!! I have never had gotten a math book at our school. They don't have enough and so they didn't give out any at all!!

2007-07-12 09:53:32 · update #1

8 answers

The answer is (-x - 7)

First, you need to factor the top half of the fraction. You will get:

[(x+7)(x-7)] / (7-x)

Now, cancel out the (x-7) and the (7-x). They simplify into -1. Now, you're left with -1(x + 7), which is equivalent to (-x - 7).

Hope that helped.

2007-07-12 09:46:17 · answer #1 · answered by Anonymous · 1 0

On the top, you will notice you have a perfect square x^2 minus a perfect square 49 or 7^2.

Polynomials of this form can be changed into:
(x+7)(x-7)

You will notice that we now have an (x-7) on the top and a (7-x) on the bottom.

These two are almost equal; in fact one is just the other multiplied by negative 1.

So, (x-7)/(7-x) equal -1.

Leaving us with (x+7)*-1

Or: -x-7

2007-07-12 16:50:43 · answer #2 · answered by Anonymous · 0 0

-(x+7) is your answer....

x^2-49 can be factored into (x-7)(x+7) so... the x-7 cancels and your left with -(x+7)

2007-07-12 16:53:14 · answer #3 · answered by hatishbee 1 · 0 1

x^2-49/7-s = -1(7-x)(x+7)/(7-x)

Cancel the (7-x) and you get -(x+7) or -7-x

2007-07-12 16:49:05 · answer #4 · answered by andrek 1 · 0 0

It gets easier once you find that
x^2 - 49 = (x+7)(x-7) = -(7+x)(7-x)

Now, solve
-(7+x)(7-x)/(7-x)

2007-07-12 16:47:13 · answer #5 · answered by Raymond 7 · 0 0

(x^2 - 49) / (7 - x)

factor

{(x - 7) (x + 7) } / (7 - x)

factor out -1
{-1 (7 - x) (x + 7) } / (7 - x)

simplify
-1(x + 7)

distriubte
-x - 7

2007-07-12 16:48:52 · answer #6 · answered by      7 · 0 0

Try factoring the numerator. Hint: the answer is in your algebra book.

2007-07-12 16:49:51 · answer #7 · answered by Rocket Scientist X 2 · 0 0

(x+7)(x-7)/-(x-7) = -(x+7) = -7 - x.

2007-07-12 16:47:05 · answer #8 · answered by John V 6 · 0 0

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