HELP again. algebra.?

0 ⤊

HELP again. algebra.?

25s^4-121
and
625r^4-p^4

2007-07-12 09:36:10 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3 answers

625r^4-p^4= (25r^2 -p^2) ( 25r^2 +p^2)
= (5r -p)(5r +p) ( 25r^2 +p^2)

2007-07-16 09:37:57 · answer #1 · answered by robert 6 · 0⤊ 0⤋

Factorise??
Question 1
(5sÂ² - 11) (5sÂ² + 11)

Question 2
(25rÂ² - pÂ²) (25rÂ² + pÂ²)
(5r - p) (5r + p) (25rÂ² + pÂ²)

2007-07-12 17:00:05 · answer #2 · answered by Como 7 · 0⤊ 0⤋

(1) 25s^4 = (5s^2)^2

121 = 11^2

a^2 - b^2 = (a+b) (a-b) .... Hope you know this one
So, (5s^2)^2 - 11^2 = (5s^2 + 11) (5s^2 - 11)

(2) 625r^4 = (25r^2)^2
p^4 = (p^2)^2

So, (25r^2)^2 - (p^2)^2 =(25r^2 + p^2) (25r^2 - p^2)

2007-07-12 16:41:34 · answer #3 · answered by Lain Lain 3 · 0⤊ 0⤋