Simplifying Radical Expressions?

Question

Simplifying The Radical Expressions

2√(3y/7)


1/3√(7/32x^2)

thanks if you can help.

Answer 1

2√(3y/7)
=2√(21y/49)
=(2/7)√(21y)

1/3√(7/32x^2)
= (1/3)√(14/64x^2)
=(1/3)(1/8x)√(14)
=√(14)/(24x)

Answer 2

Hi,

2√(3y/7)

Multiply top and bottom by √7 to eliminate the radical in the denominator.

2√(3y)
---------
....√7


2√(3y)*√7
-------------
....√7*√7


2√(21y)
-------------
....√49

....____
2√(21y)
----------- <== answer
....7


1/3√(7/32x^2)

Simplify the denominator by taking out a 4x. Then multiply top and bottom by √2 to eliminate the radical in the denominator.

1√7
-----------
3√(32x²)


1√7
-----------
3*4x√2


1√7*√2
-------------
12x√2*√2


1√14
--------
12x*2

..__
√14
------ <== answer
24x


I hope that helps!! :-)