find the gcf of set of monomials 594, 108?

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find the gcf of set of monomials 594, 108?

2007-07-12 08:33:42 · 4 answers · asked by peaches 1 in Science & Mathematics ➔ Mathematics

4 answers

2007-07-12 08:44:24 · answer #1 · answered by therealchuckbales 5 · 0⤊ 0⤋

Write the prime factorization of each number:

594 = (2^1)(3^3)(11^1)
108 = (2^2)(3^3)

The greatest common factor of two numbers is the product of the LEAST power of each factor that occurs in each prime factorization.

gcf(594, 108) = (2^1)(3^3) = 54

Answer: 54

2007-07-12 15:56:51 · answer #2 · answered by mathjoe 3 · 0⤊ 0⤋

594 = 2*3*3*3*11
108 = 2*2*3*3*3
Thus GCF is 2*3*3*3 = 54

2007-07-12 15:46:14 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋

gcf 54
54*11=594
54*2 = 108

2007-07-12 15:45:26 · answer #4 · answered by xandyone 5 · 0⤊ 0⤋