a pipe is30 3/4 ins long five pieces each 4 1/3 in long are cut from the pipe how many ins of pipe remain?

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2007-07-12 07:59:01 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

123/4 - 65/3 = 109/12 inches

109/12 inches remain.

2007-07-12 08:03:05 · answer #1 · answered by Anonymous · 0⤊ 0⤋

30 3/4 - 5(4 1/3) =
30 3/4 - 21 2/3 =
123/4 - 65/3 =
369/12 - 260/12 (12 is the lowest common denoinator) =
109/12 = 9 1/12

2007-07-12 15:10:23 · answer #2 · answered by barelyblue82 3 · 0⤊ 0⤋

30 3/4 " = 123 / 4 " = 369 / 12"
5 x 13 / 5" = 65 / 3" = 260 / 12"
Remainder = 109 / 12" = 9 ft 1 in

2007-07-12 17:19:34 · answer #3 · answered by Como 7 · 0⤊ 0⤋

30 3/4 -
5 * (4 1/3) = 21 2/3
common denominator is 12 so

30 9/12 - 21 8/12 = 9 1/12

2007-07-12 15:07:48 · answer #4 · answered by StaticTrap 3 · 0⤊ 0⤋