calculate the theoretical yeild of the product
1-(4-methoxyphenyl)-2-methylpropan-1-ol
180.21 g/mol
2-bromopropate 1.48 g
molar mass 123.0 g/mol
4-methoxybenzaldehyde 0.68g
molar mass 136.15 g/mol
2007-07-12 07:13:24 · 2 answers · asked by sippy85 1 in Science & Mathematics ➔ Chemistry
It's a Reformatzky reaction. Let 2-bromopropanoate ester be called BP. Let the methoxybenzaldehyde be called MB. Let the Reformatzky product be called RP.
1.48gBP x 1molBP/123gBP = 0.0120molBP
0.68gMB x 1molMB/136gMB = 0.005molMB
So the 4-methoxybenzaldehyde is the limiting reagent, giving 0.005 mol Reformatzky product.
0.005molRP x 180gRP/1molRP = 0.9g RP theoretical yield
2007-07-12 07:23:13 · answer #1 · answered by steve_geo1 7 · 1⤊ 0⤋
Something is missing. Is this a Grignard reaction?
Try looking at it again, check the spellings carefully, and repost.
2007-07-12 07:22:07 · answer #2 · answered by Fly On The Wall 7 · 0⤊ 0⤋