How to calculate the percentage of acetic acid of vinegar?

Question

i know that the percentage of acetic acid is computed as the volume of soduim hydroxide times its normality equals the number of milligram equivalents of acetic acid neutrilized. The equivalence of acetic acid is 60.0mg or .060g. the 10mL sample of vinegar weights 10.05g. and the volume of sodium hydroxide is 12.54 mL. So how can i calculate the percentage of acetic acid? also i know that vinegar is essentialy a dilute solutin of acetic acid in water, and the law requires that vinegar be at least 4% acetic acid by weight.

Answer 1

Normality of NaOH = ? (needed to calculate the % acetic acid)

assume 0.1 N NaOH

mL NaOH x N of NaOH = milliequivalents of acetic acid

12.54 mL x 0.10 = 1.254 meg of Acetic Acid
1 meq of acetic acid = 0.060 gram

1.254 meq x 0.060 = 0.07524 grams acetic acid
0.07524 gm acetic acid / 10.05 gm vinegar = 0.749%

Answer 2

Note that vinegar contain acetic acid. NaOH + CH3COOH = CH3COONa + H2O The reaction ratio is 1:1 Hence No. of mole of NaOH = No. of moles of acetic acid. No. of moles of acetic acid = 0.2mole/L x 0.027L = 0.0054mole.This is the concentration of acetic acid in the DILUTED vinegar. The concentration of acetic acid in the original vinegar = 0.0054 x 50/5 = 0.054mole of acetic in 5mL of vinegar. This will be 0.054 x 60.02 = 3.24gacetic acid in 5ml vinegar= 64.80g acetic acid/100g vinegar= 64.80%.

Answer 3

You don't give the molarity of NaOH solution. Let's suppose it's N. Let vinegar be called V. Let acetic acid be called HOAc. Molecular weight HOAc = 60.

12.54mLNaOH/10.05gV x NmolNaOH/1000mLNaOH x 1molHOAc/1molNaOH x 60gHOAc/1molHOAc x 100% = %HOAc

Answer 4

Can't tell. You need to provide the normality of the hydroxide, which you haven't. Also, most vinegar is labled as to it strength.

Answer 5

No calculation is really required. Just look on the label.

Answer 6

5% mostly