A sample of Sodium Chloride solution has a total mass of 51.623 grams of NaCL in a total volume of 834.21mL of solution. Calculate molarity?
2007-07-12 05:43:07 · 6 answers · asked by ... 3 in Science & Mathematics ➔ Chemistry
Molecular weight NaCl = 58.45 g/mol
51.623 g / 58.45 = 0.8831 moles NaCl
834.21 mL = 0.83421 L
M = 0.8831 / 0.83421 = 1.0587 M
2007-07-12 05:49:44 · answer #1 · answered by Dr.A 7 · 0⤊ 0⤋
Molarity is concentration (n/v=C) first find the moles (n) by taking your mass divided over your molar mass (you will find the molar masses of Ag etc. on the periodic table of course) then you take that number and put it divided over your 0.335L of solution (because it has to be in Liters, so the final units are mol/L) Happy Chemistry-ing!
2016-05-20 15:19:53 · answer #2 · answered by ignacia 3 · 0⤊ 0⤋
divide 51.623 by the molar mass of NaCl (something like 22.98977 + 35.453, not sure about that); now take that number, which is the moles of NaCl and divide by .83421 Litres.
2007-07-12 06:00:50 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Atomic weights: Na=22.989 Cl=35.453 NaCl=58.442
Let the solution be called S
51.623gNaCl/834.21mLS x 1molNaCl/58.442gNaCl x 1000mLS/1LS = 1.0589 molNaCl/1LS
2007-07-12 05:50:42 · answer #4 · answered by steve_geo1 7 · 0⤊ 0⤋
M=mol/vol
so you must convert the grams to moles.
51.623 NaCl/58g=0.890 mol
convert mL to L-----> 0.83421L
0.890 / 0.83421 = 1.06
M= 1.06
2007-07-12 06:02:20 · answer #5 · answered by ♣DreamDancer♣ 5 · 0⤊ 0⤋
51.623*1000/(58.5*834.21)
2007-07-12 06:03:45 · answer #6 · answered by ag_iitkgp 7 · 0⤊ 1⤋