Need help solving a chemistry totration prob.?

Question

If you titrate 1.502g of KHC8H4O4 with 37.28 ml of NaOH solution what is the concentration of the NaOH solution?

i got the eq. as KHC8H4O4+NaOH>KNaC8H4O4+H2O

Also, i know u need to know the number of moles to determine of NaOH in 37.28 ml or 0.03728l .

Pleas help

Answer 1

First, you must convert the potassium hydrogen phthalate to moles. It's molar mass is 204.23 g/mol.

1.502 g / 204.23 g/mol = mol

Take the number of moles times the stoichiometric factor. From your equation, you can see that one mole of sodium hydroxide reacts with one mol of sodium hydroxide.

You now have the mol of NaOH and the L of solution. Divide moles by liters to get the concentration of the NaOH.

Answer 2

Molar mass 204.22 g/mol

Potassium hydrogen phthalate moles = 1.502/204.22
= 0.00735mol

(x/1000) * 37.28 = 0.00735mol
........
x= 0.197mol/dm^3
concentration of NaOH = 0.2mol/dm^3

Answer 3

23.45