First of all, you should know that if you substitute a number
into f[x], and the result is zero, then you have a factor of f[x].
Because the constant is 21, whose factors are 1,3 and 7,
I tried first f[1], no luck, and then f[-1], which gave f[-1]=0,
so, giving [x+1] as a factor.I then divided f[x] by x+1,giving
x^3 -3x^2-7x+21, which I will now call g[x]. The constant is 21,
so for the same reasons as before, I tried g[3], which =0. So
[x-3] is a factor. I then divided g[x] by x-3, giving x^2-7, which
you may recognise as the difference of two squares. so, f[x]
factorises to:[x+1][x-3][x+rt7][x-rt7]. the two irrational roots
positive root 7, and negative root7, you will have to find
yourself, I have no calculator.I have assumed a lot here, that
you can do long algebraic division, an you follow the method
of finding factors by inspection. hope it helps, Twiggy.
2007-07-12 11:48:33
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answer #2
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answered by Twiggy 7
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