algebra help?

1 ⤊

multiply and simplify.

2x^2-2/x^2-6x-7 * (x^2-10x+21)

2007-07-12 05:15:36 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2 answers

2x^2 - 2/x^2 - 6x - 7(x^2 - 10x + 21)
2x^2 - 2/x^2 - 6x - 7x^2 + 70x - 147

Add like terms:

-5x^2 - 2/x^2 + 64x - 147

2007-07-12 05:20:04 · answer #1 · answered by yeeeehaw 5 · 1⤊ 0⤋

I think you ment (2x^2-2)/(x^2-6x-7)*(x^2-10x+21)

to solve that we get:

2(x-1)(x+1)(x-7)(x-3)/[(x-7)(x+1)]
the (x-7) & (x+1) terms cancel to get:
2(x-1)(x-3)

2007-07-12 12:28:31 · answer #2 · answered by 037 G 6 · 0⤊ 0⤋