2007-07-12 04:53:26 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Physics
(°C x 1.8) + 32 = °F
e.g. (35°C x 1.8) = 63....63 +32 = 95°F.
(If you need the other way... (°F - 32) ÷ 1.8 = °C)
2007-07-12 05:14:31 · answer #1 · answered by Norrie 7 · 0⤊ 0⤋
farenheight = 9/5 celcius + 32
celcius = 5/9 (farenheight - 32)
2007-07-12 11:57:56 · answer #2 · answered by Anonymous · 1⤊ 1⤋
C x 1.8 + 32 = F
For example, 100C = 100 x 1.8 + 32 = 212 F
2007-07-12 12:10:14 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
Firstly, it's fahrenheit. And then, to answer your question:
Tc = (5/9)*(Tf-32)
Tc = temperature in degrees Celsius
Tf = temperature in degrees Fahrenheit
2007-07-12 12:00:15 · answer #4 · answered by Astromaniac 4 · 0⤊ 0⤋
5/9(tºf-32º)=tºC f>c.
9/5 tºC+32 0 0 tº F c>f
2007-07-12 12:06:06 · answer #5 · answered by Anonymous · 0⤊ 0⤋
# deg F = {(9/5) x # deg C} + 32
Reversing this:
# deg C = (5/9) x {# deg F - 32}
Hope this helps.
Luck :)
2007-07-12 14:34:38 · answer #6 · answered by Pete S 3 · 0⤊ 0⤋
www.google.com - celcius to farenheight
2007-07-12 12:06:28 · answer #7 · answered by Anonymous · 0⤊ 2⤋
centigrade x 1.8 +32
i think its right!!
2007-07-12 11:58:19 · answer #8 · answered by Albus Percival Wulfric Brian Dumbledore™ 5 · 1⤊ 0⤋